Re: Struggling with a problem
Independent means that P(A_i) does not depend on whether or not A_j occured... so find the probability that A_k does _not_ occur for all your ks (hint: it's 1 - P(A_k)) and multiply them all together.
So P(no A_k occuring) = (1/2)*(2/3)*...*(n/(n+1)) which turns out to be = (n!)/((n+1)!) = 1/(n+1)
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