Hold \'em Flop Probability
I'm sure this is right out of Probability 101, but I'm clueless on statistical formulas, so...
In a hold 'em game, if you have two unsuited unconnected cards, what are the odds of flopping two pair, a set, quads or a fullhouse. I've read flopping two pair is 49 to 1, but I'm curious how the odds improve with the other (unlikely) additional favorable flops.
Thanks.
Sparks
|