Re: probability to be beat here?
No possible flush?
Q-X, 7-X, J-10, J-9, J-8, J-3, T-9, T-8, T-3, 9-8, 9-3, 8-3, J-J, T-T, 9-9, 8-8, 3-3.
I came up with 429 combinations beat you. If that's right, a random hand against you will beat you 43.33% of the time. You'd need inclusion/exclusion to solve this exactly I believe, but that could get really hairy. Against 3 people, it looks like you can safely expect to lose if the hands are indeed random.
|