Re: Probability in bowling question
The convolution of two normal distributions in another normal distribution. In this case, it will have mean of mean1-mean2, and sd of sqrt(sd1^2+sd2^2). Thus for bowlers with aves of 220 and 195 and sd's of 40 and 30 pins, mean=25, sd=50, so bowler 2 should win about 31% of the time.
Craig
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