Re: Pocket aces. By autoshuffler.
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Lets say you played 50 hands/h so it makes 100 hands total. You will get aces 1/51+1/50. So it is only <40% that you even get aces on that 100 hand run. (1/51+1/50)^14 wich comes down to 2.33849641 × 10^(-20) wich is 4.27625203 × 10^19. Well my calculation shows only when you get aces 14 times in a row. If someone could tell me how to calculate those 86 other hands in too I would appreciate thanks.
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Also, if the OP meant "saw" as in "any player had them", it makes the event a lot less unusual - he'd expect to see them about 5 times in 100 hands anyway. 14 is still a lot, but I don't think the autoshuffler is broken, unless it can pick the aces out and stack the deck. [img]/images/graemlins/smile.gif[/img]
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Heh I automatically suspected it was that he got them [img]/images/graemlins/blush.gif[/img] well then.
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