View Single Post
  #1  
Old 11-03-2004, 05:28 AM
kongo_totte kongo_totte is offline
Senior Member
 
Join Date: Oct 2004
Location: Tullinge, sweden
Posts: 491
Default Hold Em probability question

Hello everyone!
I wonder what the exact probability is that the board pairs (or make quads) when flopped a set.
My home made calculation is:
Number of outs for pairing any of the flopped cards: 3+3+1= 7 outs.

(7/48)+(7/47)=29.47695034%

I think that would be correct. I’m less sure about my calculation that a runner runner pair will come though. Does anyone know if this is correct:

I make the calculation: (4/48)x(3/47)x10= 5.31%

29.47695034+5.31=34.7869%

Example:
Lets say I have 33 and the flop comes 2 3 4.
There is a 29.4769% chance that another 2, 3 or 4 will turn or river.

Let’s say a J falls on the turn (4/48). I then have 3 outs to the jack. (3/47). I then multiply this by 10, cause there are13-3 cards this can happen with (A 5 6 7 8 9 T J Q K).

Please, correct me if I’m wrong, probably am (I have only high school math to support this with). I know a number of probability generators can give me the right answer, but I would really like to know the calculation. Thinks it gives me a better understanding of the game.
Reply With Quote