[Mike Haven]

the way MC has done it is by saying there were 50 x 49 = 2450 ways of dealing him his two before the flop

there are 8 x 4 = 32 ways of dealing him T9 or 9T

which means it would be (2450 - 32) to 32 = 2418 to 32 = 75.6 to 1

but this is wrong in this case because we know the three flop cards (which obviously could not have been dealt to the other guy, or, vice versa, could not have flopped to create the problem we are being asked to solve)

so it should be ((47 x 46) - 32) to 32 = (2162 - 32) to 32 = 2130 to 32 = 66.6 to 1, if we leave out the pairs i mentioned earlier