[Medibart]

Here's the thing though. Let's use your example of getting 10:1 on your money and let's say you have like 4 outs on the river - about 9:1 probability. The one time you hit it has to make up for the other 8 times you miss.

If in your successful attempt you put in 2$ and won $20 but the other 8 times you missed you put in an average of 3$ you lost 24$ for a net loss of 4$. So even though you had good pot odds each time and you matched the statistical expectation, this was not a profitable play. That is why it seems to me that in the basic pot odds equation, the wager would somehow have to be a constant, otherwise there is no guarantee of profitibility considering sometimes you are winning a little and sometimes you are losing a lot.