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Old 10-14-2005, 06:42 PM
PaultheS PaultheS is offline
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Join Date: Jul 2004
Posts: 82
Default Re: AA KK AK what are the chances

One opponent, given that you have AK, has:

C(3,2) + C(3,2) = 3 + 3 = 6 ways to get AA or KK out of C(50,2) = 1225 possible hands. So, the probability he has AA or KK is 6/1225 = 0.004898.

With no other information, the probability he has AA or KK is (C(4,2) + C(4,2)) / C(52,2) = 0.009050.

So, the fact that you have AK decreases the chances he has AA or KK from 0.9050% to 0.4898%.
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