Re: Few questions..
Maybe I'm missing something...
If you have 52 cards, and you keep choosing cards randomly until you either a) hit an A or b) go through 48 w/o, here's what I get.
Choosing 48 cards from 52 such that none are Aces is the same as choosing 4 cards from 52 such that all 4 are Aces. So, 52 c 4 = 270,725.
Doesn't this mean that you should be able to do it once every 270,725 times on average? And, note that this doesn't even include the free games you win when you hit an Ace right off the bat (1/13 chance).
So I think if you run this game, you basically go broke, since people will win a ton from you. Where is my math wrong?
-RMJ
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