Re: Calculating odds of two players getting pocket pairs
The chance that your opponent(assuming you're playing heads up) has a pp in 1/17, on any given hand. The fact that you may have a pp on this hand changes nothing (or very nearly so). If he has a pp, just a hair below 1/3 of them are higher than your TT. (tiny chance he also has TT)
This means that heads up (estimated slightly for the sake of practical, on the spot math) your TT will face a higher pair 1/51.
Of course, in a full game the odds change with each additional player.
As far as losing set over set: If you flop a T it is less than 1/8.5 that your opponent also flops a set. Since one card on flop must be a T, that only leaves him 2 to catch a Q (for example). But of course, with a hand this strong he may well play on and catch on the turn or river.
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