[getfunky]

The probability of getting a full house by the river when you only have one pair is so small, its probably not worth it, but I am trying to learn so bear with me.

Would you first calculate the odds of tripping your pair by the river:
Check w/1 card remaining(.04255)
Check w/2 cards remaining(.08418)

Then find the odds that one of the unpaird cards pairs up:
Check w/1 card remaining(.19148)
Check w/2 cards remaining(.34968)

Then Multiply the two together.
Check w/1 card remaining(.00814)
Check w/2 cards remaining(.02943)

Seeing that I need to have both my pair hit the third card and one of the unpaird cards pairing, I am not sure weather I need to calculate the possibilities with one or two cards remaining.

Thanks for the help
-ST