[McCranky]

I'm not sure what you did there but i think the odds that three people have three different pair are:

78(pairs)/1326(combin) X 72(2nd guy)/1225(leftover combins) X 66(3rd guy)/1126

For .000202 or .0202 %

The Probability that the flop would yeild the 3 cards needed for 3 sets is:

8(combinations of 3 cards)/46C2(15,180) = .000527

So the probability of 3 people getting pairs and then all three getting sets is:
.000202 X .000527 = .000000106 or 9.294 million:1

hmm seems high