Re: Odds of pockets aces being dealt twice in the same round
What is C(52,4) and how do I calculate this?
Number of ways to choose 4 things out of 52 irrespective of order, or "combinations of 52 things taken 4 at a time". It is equal to 52*51*50*49/(4*3*2*1) or 52!/48!/4!. There are 52 ways to choose the first, 51 ways to choose the second, 50 ways to choose the third, and 49 ways to choose the 4th, and then we divide by 4! different orders they can be chosen. In general, C(n,k) = n!/(n-k)!/k!. This can also be evaluated in Excel with the function COMBIN, or on some calculators.
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