Re: Standard Deviation Question, How to do it?
These numbers are just data points of the percent of my finish.
Place Finished
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Total Entrants
This was done in an attempt to normalize the data because the number of entrants is variable, although it's generaly about 2,000.
I simply want to gain some insight into my performance, whatever might be the best metric.
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A power distribution is a common model, and easy to use. You assume that the probability of fraction X or less of the players finishing ahead of you is X^a for some a. Using your data suggests a = 0.2894. This imples a 67% chance of finishing in the top quarter, 82% chance of finishing in the top half and 92% chance of finishing in the top three-quarters. Of course given only four tournaments and the arbitrary model, I wouldn't put a lot of weight on these statistics.
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This sounds about right to me but my instant problem is I can't determine your value, a, unless I can determine x.
What I can gained from your post is for the data points:
finished at percent 4, 15, 33, 47
there exists some power distribution function, x, where the quadrant (or other segmentation) is x ^ a.
So I attempted to calculate the upper quarter.
1
- = x ^ a
4
and x is unknown to me and therefore a is unknown.
Did I miss something or is there a better suggestion?
Statistics is not my "strong suit", unfortunately it is not the type of math I have been doing.
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