[J'adoube]

It shouldn't be so hard to find the probability of finding the highest number number for 2 or 3 dice. And then it should be easy...

Viz for 2 Dice P(1 high)= 1/36

P( exactly 2 high)=3/36

P(exactly 3 high)= 5/36

P(exactly 4 high)= 7/36

P( exactly 5 high) = 9/36

P(exactly 6 high) =11/36.

Now it should be easy to compute the 1-1 1-2 and 2-2 match ups.