MUCH SIMPLER WAY!
I realized that there is a much simpler way to do these problems than the way I did them on the WPT thread. You don't need all the permutations and combinations. For example, for KK vs. AA you can just do this for the EXACT answer:
6*9/C(50,2) - C(9,2)/C(50,4) = 1 in 22.77.
The second term is the probability of 2 people having AA. There are C(9,2) ways to pick the two players, and 1 way they can have all 4 aces out of the C(50,4) ways they can have 4 cards.
All the problems can be done almost this simply, except they will have 3 terms instead of 2 for the desired level of accuracy.
-Bruce
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