Re: newbie question about options
You're mistaken.
Sure, an american option cannot be expressed analytically (thats what discrete approximation models are for) but an american call is the same as a european call under geometric brownian motion, the assumption for BS. Its never preferable to exercise an american call before its expiry.
e.g. S(t) = price of security at time t. If an american call (Price C,Strike K,Expiry T) is in the money, at time t1 say, t1<T, you can exercise and realise a time-T gain of:
[S(t1)-K]e^r(T-t1)
If instead you sell short at T1, stick the funds S(t1) into a bank paying continuously compounded interest at rate r (as above), then at time T buy the stock at the minimum of K and S(T) with the bank money you have a time-T gain of:
S(t1)e^(T-t1) - min {K, S(T)}
which is greater. So its never preferable to exercise early, thus its the same expected value as its european sibling, under Black-Scholes and its assumptions.
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