[Mark1808]

Thank you so much, I'm getting someplace. I think I understand the choose method now. 11 chose 2 gives the number of ways you can get 2 diamonds from remaining 11 diamonds, multiply by the number of non-diamonds (each non-diamond can match up with each 2 card diamond combo) divided by 50 chose 3 (the number of possible flops).

So the possibility of flopping a flush would be (11 choose 3) / (50 choose 3) = .84% Damn!! Thank you Gambling Mouse!

Now the odds of hitting the flush with two cards to come would be p(diamond turn & blank card river) + P(blank card turn & diamond card river) + P(Diamond card turn & river)

= 9/46 * 37/45 + 37/46 * 9/45 + 9/46 + 8/45 = 35.65%?

Can you do that with the choose method too? I am off I get
(9*38)+ (9*8) / (47 choose 2)= 38%