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Old 03-31-2005, 04:18 PM
NegativeEV NegativeEV is offline
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Join Date: Jun 2004
Posts: 118
Default Re: Math Question

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It's also likely that I've lost some hearts to some of the other hands that have folded, or are in any of the players cards still in the hand.

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I think you understand this, but you do not change your "out count" for the fact that hearts could have been in the other player's hands that folded (unless you are cheating and know hearts were folded). You determine the probability of catching your desired card based on the informaiton available. So if you only think the hearts are good outs and you can account for 4 hearts you have 9 outs- period. Then that 9 outs is evaluated against the unseen cards you are drawing from. This means catching a heart on the next card is 9/47 or 19.15% or roughly 4:1 against. The fact that other players may have mucked a heart does not enter into this analysis.

Again, I think you understand this, but your sentence above could be confusing to folks who are learning how to calculate outs/probabilities/etc.
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