Re: If player 1 holds AA, the probability that player B has AA is?
So to summarize...
Given a 10 player table...
If player A(you) has AA, the odds of specific player B(me) having AA = 1/1225
If player A(you) has AA, the odds of any other player B having AA = 9/1225
The odds of any player A and any other player B both having AA = 10c2 * 6/52c2 * 1/50c2 = ~1 in 6016
Given a PT database of 110,000 hands, I make the probability of you not having your AA run into another AA... at worst(if you play all 10 handed games) to be = .0258 = ~1 in 39
You have been lucky!! ...on average you should have had it happened about 3 times!!!
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