Re: If player 1 holds AA, the probability that player B has AA is?
Well, for 1 player to not have AA is 1224/1225 so for two players to not have AA is (1224/1225 * 1223/1224) and so on. so for a full table against 9 other players, one of them having AA is = ~.007. or .7% (or ~ 1/136). Seems a bit high to me but if you figure that you get AA 1/221 hands this situation occurs 1 time every 30056 hands delt.
|