[bobman0330]

OK, P(2 identical boards)=P(flop match)*P(turn match)*P(river match)= P(flop)*1/49*1/48= P(flop)/2352.

P(flop)
We need a 6 of one suit, a 3 of the same suit, and a 2 of another suit. P= 4/52*1/51*3/50*6. 6 is 3 P 3, for different flop orders. P = 72/ 132600= 1 in 1841 and 2/3= 5.430E -4.

P(total)=72/311875200= 1 in 4331600= 2.309E-7.

so, 4.33M to 1. PS has dealt a little more than 1B, PP another billion and a half. so, probably a couple hundred same board hands dealt overall online (discounting folded before river hands and non-flop games).

People better than me at probability, how'd i do?