Re: AK against AA or KK
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I don't what your thought process was when you multiplied that number by 9*2, so I can't tell you where you are going wrong, except to say that it's not how you do it.
Tell me what you were thinking and maybe I can explain.
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His answer is the first term of the inclusion-exclusion solution. It is not exact because it double counts the times that two players hold AA or KK, so this must be subtracted off. It would be exact if no more than one player could hold AA or KK.
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