Re: AK against AA or KK
kyro,
(3/50) * (2/49) is the correct way to calculate that one particular player is dealt one particular hand, either AA or KK.
I don't what your thought process was when you multiplied that number by 9*2, so I can't tell you where you are going wrong, except to say that it's not how you do it.
Tell me what you were thinking and maybe I can explain.
I solved it using the inclusion-exclusion principle, the formula for solving P(A or B or C ...) where, in this case, the events are:
A = opponent 1 has AA or KK
B = opponent 2 has AA or KK
etc
gm
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