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-   -   I think this is right. (http://archives2.twoplustwo.com/showthread.php?t=314686)

KenProspero 08-13-2005 10:41 PM

I think this is right.
 
Hold-em Post flop.

You're holding J [img]/images/graemlins/diamond.gif[/img]T [img]/images/graemlins/diamond.gif[/img]

Flop is A [img]/images/graemlins/diamond.gif[/img]Q [img]/images/graemlins/diamond.gif[/img] 6 [img]/images/graemlins/club.gif[/img]

25 in the pot (heads up) and opp bets $60, all in.
You're sitting with 12 outs (maybe discount to 11) and 1.4-1 pot odds to call an all-in better (heads up).

Easy call, right?

mosdef 08-13-2005 11:14 PM

Re: I think this is right.
 
it's not such an "easy" call. i think this is slightly +EV, something like your expected profit if you call is $0.50. so it is a call, but it's not a huge money maker.

Luzion 08-13-2005 11:23 PM

Re: I think this is right.
 
mosdef, are you really an actuary?

Oh and btw, you have to call this everytime unless you have a really good reason to believe he has a flopped set... in which case it would be -EV to call....Also if he holds Kd and has an Ace or Queen as his sidecard, it would be slightly -EV to call as well...

wuarhg 08-13-2005 11:31 PM

Re: I think this is right.
 
This is kind of a thread hijacking since the title goes along fine with my very easy query. So . . . I am just trying to determine what percentage of all hands the following are.

AA KK QQ JJ TT 99 88 77 66 55 44 = 66 ways
AKo AQo AJo ATo A9o A8o A7o A6o A5o A4o = 160 ways
AKs AQs AJs ATs A9s A8s A7s A6s A5s A4s A3s A2s = 48 ways
KQo KJo KTo K9o K8o K7o = 96 ways
KQs KJs KTs K9s K8s K7s K6s K5s K4s = 36
QJo QTo = 32 ways
QJs QTs Q9s = 12 ways
JTo = 16 ways
JTs J9s = 8 ways
T9s = 4 ways

For a total of 478 ways.

So that means... 478 / 1326 = ~36% of all hands?

spaminator101 08-13-2005 11:32 PM

Re: I think this is right.
 
i call
you will usually make money but even if you dont playing the marginal hands helps your image unless you were on a low bankroll i would call this

Luzion 08-13-2005 11:50 PM

Re: I think this is right.
 
[ QUOTE ]
This is kind of a thread hijacking since the title goes along fine with my very easy query. So . . . I am just trying to determine what percentage of all hands the following are.

AA KK QQ JJ TT 99 88 77 66 55 44 = 66 ways
AKo AQo AJo ATo A9o A8o A7o A6o A5o A4o = 160 ways

[/ QUOTE ]

I think this is wrong...it should be 120 ways...I think you accidently also counted the hands that would be Axs


[ QUOTE ]
AKs AQs AJs ATs A9s A8s A7s A6s A5s A4s A3s A2s = 48 ways
KQo KJo KTo K9o K8o K7o = 96 ways

[/ QUOTE ]

I think you counted the Kxs hands again... Im pretty sure it should be 72 ways...
[ QUOTE ]
KQs KJs KTs K9s K8s K7s K6s K5s K4s = 36

QJo QTo = 32 ways

[/ QUOTE ]
24 ways...

[ QUOTE ]
QJs QTs Q9s = 12 ways
JTo = 16 ways

[/ QUOTE ]
12 ways, since you counted JTs

[ QUOTE ]
JTs J9s = 8 ways
T9s = 4 ways

For a total of 478 ways.

So that means... 478 / 1326 = ~36% of all hands?

[/ QUOTE ]

Now it should be 402/1326 = 30.3%

wuarhg 08-14-2005 10:43 AM

Re: I think this is right.
 
Oh, okay thanks. So AKo = 12 ways and AKs = 4 ways and they both add up to 16 ways. I got it now [img]/images/graemlins/ooo.gif[/img]

mosdef 08-14-2005 11:38 AM

Re: I think this is right.
 
1. not quite. i work for an actuarial consulting firm, will be an actuary next year

2. my statement about the EV is based on his assumptions - that he needs to hit one of his 11 outs to win.


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