sthief09
05-10-2004, 11:58 AM
Please tell me if/where I'm going wrong. I'm trying to figure out how many hands a person needs to tell if he's a winning player given a certain SD and winrate.
The way I'm thinking of it is in samples of 100 hands. Winrate is x and SD is s. Since n is in terms of 100 hand samples (number of hands divided by 100), I need to do a t-test. The null hypothesis would be that x is greater than 0, or in other words, the player is a winning player on a 95% CI.
we reject if T < t
t can't be exact since we're solving for n, but for a = .05, and v somewhere between 40 and >100, so it's around 1.65-1.69
T = (x - 0)/(SD/sqrt(n)) = x*sqrt(n)/SD
for me, x = 4.46 and SD is 17.24, so
T = .259*sqrt(n) < 1.69 (1.69 since we're starting for the smallest value of n)
n > (1.69/.259)^2
n > 42.57
so according to this, with a winrate of 4.46 BB/100 and a SD of 17.24/100, you'd only need 4,257 hands to be a proven winner. that doesn't make any sense to me. Please tell me where I went wrong.
The way I'm thinking of it is in samples of 100 hands. Winrate is x and SD is s. Since n is in terms of 100 hand samples (number of hands divided by 100), I need to do a t-test. The null hypothesis would be that x is greater than 0, or in other words, the player is a winning player on a 95% CI.
we reject if T < t
t can't be exact since we're solving for n, but for a = .05, and v somewhere between 40 and >100, so it's around 1.65-1.69
T = (x - 0)/(SD/sqrt(n)) = x*sqrt(n)/SD
for me, x = 4.46 and SD is 17.24, so
T = .259*sqrt(n) < 1.69 (1.69 since we're starting for the smallest value of n)
n > (1.69/.259)^2
n > 42.57
so according to this, with a winrate of 4.46 BB/100 and a SD of 17.24/100, you'd only need 4,257 hands to be a proven winner. that doesn't make any sense to me. Please tell me where I went wrong.