4 flush on board, 5 players, no one has the flush--what are the odds?

[bdk3clash]

SSIA.

[BruceZ]

On river, assuming random hands:

C(38,10) / C(47,10) = 9.1%.

[easypete]

[ QUOTE ]
On river, assuming random hands:

C(38,10) / C(47,10) = 9.1%.

[/ QUOTE ]

I'm still trying to relearn this combination thing (helps me to verbalize).

C(38,10) --> Number of possible combinations of 10 cards out of 38. This is the 39 non-flush cards - the non-flush card on the board = 38. 10 cards dealt to 5 players.

C(47,10) --> Number of combinations of hole cards for 5 players from the rest of the deck (less board).

If you are one of the players, and posses no flush cards, then it changes to:

C(36,8)/C(45,8)? 14%?

Is this correct?

[sthief09]

Is this correct?

yes