roGER
04-08-2004, 12:32 PM
Hello everyone,
In "Gambling Theory and Other Topics" Mason gives a formula you can use to work out how many sessions you will lose.
Solving for "X" with my own results I arrived at a figure of -0.11
In Mason's example, X = -0.13
He then wrote:
"From a normal distribution table, we see that -0.13 standard deviations corresponds to the 44.83 percentage point. This means that with the parameters given you should expect to be a loser in about 45% of your five hour playing sessions."
Could one of you with access to a suitable normal distribution table tell me what percentage -0.11 corresponds to?
I've tried finding one on the internet, but have been baffled by the amount and different types of table available.
Thanks,
- roGER
In "Gambling Theory and Other Topics" Mason gives a formula you can use to work out how many sessions you will lose.
Solving for "X" with my own results I arrived at a figure of -0.11
In Mason's example, X = -0.13
He then wrote:
"From a normal distribution table, we see that -0.13 standard deviations corresponds to the 44.83 percentage point. This means that with the parameters given you should expect to be a loser in about 45% of your five hour playing sessions."
Could one of you with access to a suitable normal distribution table tell me what percentage -0.11 corresponds to?
I've tried finding one on the internet, but have been baffled by the amount and different types of table available.
Thanks,
- roGER