3 people flopping a set?

[Ponks]

This happened to me the other day where 5 people were in the pot, and 3 outta the 5 flopped a set. I held 10/10, button held A/A, and 6th position held 7/7. Flop comes A, 10, 7. Just curious if there is anyway to calculate this. I've never seen it happen before, and needless to say, me and the 77's lost a decent amount of money. If there is no way to calc this, sorry for asking, Thanks =)

Ponks

[bigsooner]

its easy is the question what are the odds after they all have different pairs?? the answer would be 6/46*4/45*2/44

0.000527009 or one in 1897.5

[McCranky]

I'm not sure what you did there but i think the odds that three people have three different pair are:

78(pairs)/1326(combin) X 72(2nd guy)/1225(leftover combins) X 66(3rd guy)/1126

For .000202 or .0202 %

The Probability that the flop would yeild the 3 cards needed for 3 sets is:

8(combinations of 3 cards)/46C2(15,180) = .000527

So the probability of 3 people getting pairs and then all three getting sets is:
.000202 X .000527 = .000000106 or 9.294 million:1

hmm seems high

[Ray Zee]

its those occurances where three or more people have a different pair and at least three see the flop. then after that happens its 1899 to one.

anyway i have seen it happen twice that i can remember in 35 years.