Adde
02-17-2004, 01:42 PM
Let's have a discussion about suited, zero-gap, max stretch connectors (45s-TJs) in multiway pots.
You will flop any draw about 1/6, and from there you will make your str8 or flush about 1/3, thus you will make the hand about 1 time of 18. The numbers are actually a little worse, but considering that some of your made hands will lose we say that you make a winning made hand 1/18.
When you miss the flop you will invest 1 small bet (sb), and when you hit you will always take it to the river for 4 sb. Of those 18 times you will pay:
3*4 + 15*1 = 27 sb
That one time of 18 you make your hand you have to extract at least 27 sb from the other players to break even. With a 7-way pot you have 6 opponents on the flop. If 4 see the turn, 2 see the river and 1 see the showdown, you will get:
6*1 + 4*1 + 2*2 + 1*2 = 16 sb
So, where do you get those missing 11 sb to break even?
** You have to play it aggresive and extract as much as possible when you have the best of it, and also you have to play by perfect pot odds, not leaking off a bad bet here and there. Every time. One badly played hand can eat up all the profit.
** Can you get those missing 11 sb that one time when you have the winning hand? If not, you have to make one of the other 17 hands a winner:
- 2 times you will be at the river with a busted draw. The pot will be 14 sb. If 1 of 2 bets/calls will succeed you have turned the hand into a winner. If not, you have to get 4 more sb from other hands.
- 15 times you won't flop a draw. About 4 times (29%) you will pair one of your cards. If you don't play well postflop (get rid of low pairs, check-raise with top pair, etc), you can easily make this hand a loser. Another 2-3% you get more than one pair.
SOME THOUGHTS
Despite being a seemingly good multiway hand, you have to play it very well postflop to make it a winner.
Any flaws in my thinking?
How many players in the pot do you need to play these hands?
You will flop any draw about 1/6, and from there you will make your str8 or flush about 1/3, thus you will make the hand about 1 time of 18. The numbers are actually a little worse, but considering that some of your made hands will lose we say that you make a winning made hand 1/18.
When you miss the flop you will invest 1 small bet (sb), and when you hit you will always take it to the river for 4 sb. Of those 18 times you will pay:
3*4 + 15*1 = 27 sb
That one time of 18 you make your hand you have to extract at least 27 sb from the other players to break even. With a 7-way pot you have 6 opponents on the flop. If 4 see the turn, 2 see the river and 1 see the showdown, you will get:
6*1 + 4*1 + 2*2 + 1*2 = 16 sb
So, where do you get those missing 11 sb to break even?
** You have to play it aggresive and extract as much as possible when you have the best of it, and also you have to play by perfect pot odds, not leaking off a bad bet here and there. Every time. One badly played hand can eat up all the profit.
** Can you get those missing 11 sb that one time when you have the winning hand? If not, you have to make one of the other 17 hands a winner:
- 2 times you will be at the river with a busted draw. The pot will be 14 sb. If 1 of 2 bets/calls will succeed you have turned the hand into a winner. If not, you have to get 4 more sb from other hands.
- 15 times you won't flop a draw. About 4 times (29%) you will pair one of your cards. If you don't play well postflop (get rid of low pairs, check-raise with top pair, etc), you can easily make this hand a loser. Another 2-3% you get more than one pair.
SOME THOUGHTS
Despite being a seemingly good multiway hand, you have to play it very well postflop to make it a winner.
Any flaws in my thinking?
How many players in the pot do you need to play these hands?