What are the odds of flopping 2 pair in holdem??

[N4CER1]

What are the odds of flopping 2 pair in holdem?? Thanks

[sdplayerb]

i believe it is somewhere around 40:1

[Lost Wages]

If you have two cards of different rank X and Y, and you want to make two pair by pairing each of your hole cards (flop of XYZ) then there are 3*3*44 = 396 flops out of 19,600 total flops or (19,600 - 396):396 = 48.5:1 against. The odds against flopping either 2 pair, trips, a full house or quads is 27:8:1.

Lost Wages

[mr_jmac]

Hey,

I understand how you got this answer.

[ QUOTE ]
If you have two cards of different rank X and Y, and you want to make two pair by pairing each of your hole cards (flop of XYZ) then there are 3*3*44 = 396 flops out of 19,600 total flops or (19,600 - 396):396 = 48.5:1 against.

[/ QUOTE ]

Would you mind enlightening me on how to figure this out?

[ QUOTE ]
The odds against flopping either 2 pair, trips, a full house or quads is 27:8:1.

[/ QUOTE ]

Thanks,
JM

[Lost Wages]

Well, of course you have to count all the trip, full house and quad flops, being careful not to double count anything.

Again if your hole cards are X and Y with X <> Y <> Z then:

2 pair
XYZ flops = 396

Trips
XXZ flops = (3*2)/2*44 = 132
YYZ flops = 132

Full House
XXY flops = (3*2)/2*3 = 9
YYX flops = 9

Quads
XXX flops = 1
YYY flops = 1

Total flops for 2 pair, trips, full or quads = 680
So (19,600 - 680):680 = 27.8:1

Hopefully I didn't screw anything up.
Lost Wages

[Zetack]

Hey great! I just came over here intending to ask the same question (and ask what are the odds for two pair or better as well).

Thanks for anticipating my needs so well. /images/graemlins/grin.gif

--Zetack