Henke
01-21-2004, 12:02 PM
Another post here got me thinking about deriving an approximation to the odds (against one) with two cards to come given a specific number of outs. Anyway, the approximation I came up with is 23/o-0.69. This is very exact if the nr of outs equals 5 to 15, with a maximum absolute error of about 0.0058 (this is when o=9). The errors for 1 to 4 outs are (rounded to two "value-digits) 0.19, 0.069, 0.031 and 0.013. Don't know if it's practical though, it isn't really that easy to calculate that 23/5-0.69=3.91 /images/graemlins/grin.gif
To get an approximation to the odds rounded to the nearest integer, just use round(25/o-1). That gives the same result as the exact odds rounded to the nearest integer for o>2 (well, actually not when o=17,18 or 19:)).
To get an approximation to the odds rounded to the nearest integer, just use round(25/o-1). That gives the same result as the exact odds rounded to the nearest integer for o>2 (well, actually not when o=17,18 or 19:)).