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View Full Version : Help Calculating The Odds on this Roulete Bet


12-19-2005, 03:55 PM
Playing the European version (aka only 1 zero )

Betting $100 on 1st 12 and $100 on 2nd 12.
This pays 2:1 so as long as the ball is between 1-24 i get back 1:1.

Only thing making me lose is 3rd 12 and 0

so its 24/37

Is this a good bet? good ev? etc

LetYouDown
12-19-2005, 04:01 PM
EV = (24/37 * 100) + (13/37 * -200) = -$5.41 every time.

No.

12-19-2005, 04:05 PM
SURE DOES MAEK SENSE! yeah how did u figure out that equation thats crazy.

yeah in general i got like a 60ish% chance of winning tho right?

LetYouDown
12-19-2005, 04:09 PM
In the long run, 24/37 times you'll "win" $100. If it hits on 14, you bet $200 but you take back $300 for a profit of $100. Make sense?

In the long run, 13/37 times you'll lose $200. This should be obvious. 25-36 and 0. Make sense?

Edit: Yes, you will win more often than you lose (64.86% of the time). You'll just lose twice as much money as you win.

12-19-2005, 04:19 PM
yeah that makes sense now thanks.

Well what do u think of my idea.

Im gonna bet $100 dollars on 1st 12 and $100 dolalrs on 2nd 12.

If i win 10 times in a row spliting the profit won between the 2 bets.

I'll make 1135 by wining 7 bets in a row. I dunno that doesnt sound to bad.

Better yet just bet on black or red. if i bet 100 dollars i get back 1:1 if i double it up each time i win if i win 10 times in a row thats $52,000 dollars

LetYouDown
12-19-2005, 04:22 PM
For your sake, I hope you're just being a troll.

12-19-2005, 04:24 PM
Maybe it is better to bet 100$ on the first 12 and 100$ on the last 12. Make sense?

12-19-2005, 04:30 PM
why would that be a better bet

12-19-2005, 04:52 PM
Because you win only 24/37 if you bet on the first two columns, of course. So, the rest must be on the last one. That would give you a rock solid advantage!!1

MagicFlea
12-19-2005, 10:33 PM
quite simply there is no strategy of play for any -EV game that results in anything other than losing all of your money in the long run. Roulette is such a game.

if you persist in putting money on a roullete table in any combination, strategy, or tactic whatsoever, the only possible outcome is that all of your money dissapears. This is a mathematical truth as surely as 2+2=4