Odds for flopping trips with two unpaired cards in the hole..

...are?

Thanks!

[ohnonotthat]

Starting without a pair you'll flop trips 1 time in 70 give or take a few decimal points.

It's ~ 1,000-1 against flopping a full house and 9,799-1 against flopping quads.

*

I hope that helps.

- Please pay the cashier on the way out. /images/graemlins/cool.gif

[LetYouDown]

Trips, without a boat/quads:

[2 * C(3,2) * 44]/C(50,3) = ~1.35% or ~73.24 to 1

2 of either of your cards (no boat/quads restriction):

[2 * C(3,2) * 48]/C(50,3) = ~1.47% or ~68 to 1

[ QUOTE ]
Trips, without a boat/quads:

[2 * C(3,2) * 44]/C(50,3) = ~1.35% or ~73.24 to 1

2 of either of your cards (no boat/quads restriction):

[2 * C(3,2) * 48]/C(50,3) = ~1.47% or ~68 to 1

[/ QUOTE ]

Can you explain this calc format for me? Particularly what the C function is....

[LetYouDown]

C stands for Combinations, and is equivalent to the Excel function COMBIN. Basically, C(N,R) is the number of ways to select R items from a set of N items, regardless of order.

Simple example...how many different combinations of A-A are there?

C(4,2) = the number of ways to choose 2 Aces from a set of 4 Aces. Hopefully that makes sense.

Also, C(N,R) = N!/{(N-R)!R!} when N! = the product of all numbers from 1 to N.

e.g 4! = 4x3x2x1 = 24

So, C(4,2) = 4!/{(4-2)!2!} = 4!/(2!2!) = 4x3x2x1/(2x1)(2x1) = 24/4 = 6.

If you don't have Excel you can type 4 choose 2 into Google search and it will split out the number /images/graemlins/smile.gif

Let me try to explain a "little" better.

The denominator is all possible flops (50 unseen cards, and 3 are chosen randomly).

The numerator is counting how many of those combinations give you a set. Out of the 3 cards in the flop, the 2 of like rank that give you a set. Times 2 is because you don't care which of your cards hits a set.