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View Full Version : Drinking games lead to question my probability, meh

jkkkk
11-17-2005, 11:43 AM
4 random people sitting at a table, Px= Probability of the amount of left handed people at the table.

p0 = .6568

p1 = .2916

p2 = .0486

p3 = .0036

p4 = .0001

The probability that at any random table in the UK where 4 people are sat are all left handed = 1000th?

(assuming that the probability of a person being left handed is .1)
alThor
11-17-2005, 01:07 PM
Drunk posts always make more sense when you read them in reverse:

Assume P(lefty) = 10%.

Is P(all 4 people lefty) = one 1000th?

[ QUOTE ]

4 random people sitting at a table, Px= Probability of the amount of left handed people at the table.

p0 = .6568

p1 = .2916

p2 = .0486

p3 = .0036

p4 = .0001


[/ QUOTE ]

Yes.

Excellent.
Tom1975
11-17-2005, 01:10 PM
.0001=1/10,000
jkkkk
11-17-2005, 01:50 PM
[ QUOTE ]
.0001=1/10,000

[/ QUOTE ]

Correct, don't know why I feel like being stupid today.