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Yeti
11-08-2005, 01:21 PM
I know this isn't the most ideal forum, but is there any free good software? Or is there really only commercial stuff like Maple/MATLAB to choose from.

If the latter is true, if someone who has either of these could quickly run the integral of sin^6(t) between 0 and pi/2, then I could check my answer, that would also be cool.

Thanks.
TomCollins
11-08-2005, 03:12 PM
Maybe a TI-89 emulator?
eisanm
11-08-2005, 03:22 PM
I get 0.49087
TomCollins
11-08-2005, 03:27 PM
[ QUOTE ]
I get 0.49087

[/ QUOTE ]

Aha, the free software he was looking for, asking you every time he needs to know! Well done.
11-08-2005, 03:29 PM
just to clarify, you want the integral of sin(sin(sin(sin(sin(sin(t)))))) between 0 and pi/2..., right?

If so, Mathematica gives 0.689173

(Integral of (sin(t))^6 between those limits is 0.490874, but this one can be computed analytically)
elitegimp
11-08-2005, 04:15 PM
[ QUOTE ]
I know this isn't the most ideal forum, but is there any free good software?

[/ QUOTE ]

Octave (http://www.octave.org/) is a freeware Matlab clone that I've heard good things about... I haven't actually used it myself, but now that I remember it exists I'll probably install it tonight when I get home.

If you PM me, I'll reply with a basic review once I get it up and running (this weekend-ish, maybe?). Conversely, if you use it feel free to let me know your impressions (especially if you are familiar with Matlab)
irchans
11-08-2005, 05:45 PM
If f[t] = (5*t)/16 - (15*Sin[2*t])/64 + (3*Sin[4*t])/64 - Sin[6*t]/192,

then f '[t] = (Sin[t])^6,

f[Pi/2] - f[0] = 5 * Pi / 32 ~= 0.490873852123405193509788028637
Siegmund
11-09-2005, 04:00 AM
If you want only the occasional integral, there is integrals.wolfram.com , a demonstration site for Mathematica. (Believe it may only give indefinite integrals, too - but evaluating at the limits is pretty easy when it's sines at 0 and pi/2 we are talking about.)
barongreenback
11-09-2005, 03:02 PM
[ QUOTE ]
Maybe a TI-89 emulator?

[/ QUOTE ]
[ QUOTE ]
I get 0.49087

[/ QUOTE ]
I'm using a TI-83. I feel all outdated.
OTOH it did give me 0.49087 as well so maybe I won't worry.
Yeti
11-09-2005, 08:50 PM
Cheers guys. Got the right answer using pen and paper.