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What is the probability that an opponent have one or two clubs when the board has four clubs, and how do I calculate it?
In Hold'em
Martin Carlsson
Aalborg, Denmark
Hi Martin
I assume that there are 4 cards on the board, and you do not have a club. There are 46 unseen cards, and 9 clubs left. You now have to calculate the probability that he does NOT have a club. Of 46 cards 37 are not clubs.
(37/46)*(36/45) = 64%. So in 36% of they time he will have one or more clubs.
Jesper Jørgensen, Denmark
Ok,tnx
Can you recommend a book that explains standard probability?
I don't need anything fancy (jet), just an introduction.
It is ok, if it is danish.
Martin Carlsson
Aalborg, Denmark
paulish
08-29-2005, 10:57 PM
Get Chance: A Guide to Gambling, Love, The Stock Market & Just About Everything Else (http://www.amazon.com/gp/product/customer-reviews/1568583168/ref=cm_cr_dp_pt/002-0037956-2294422?%5Fencoding=UTF8&n=283155&s=books)
by Amir D. Aczel. High Stakes, 2005.
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I just finished reading it. Great book!
I can recommend it to anyone, who want an introduction to probability.
DoomSlice
11-21-2005, 11:21 AM
Questions like this are best left to the realm of theory, since the way an opponent plays a hand should tip you off more as to whether he has a club (conditional probability!).
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