A puzzle from Popular Science April 1960 issue

[bdk3clash]

(Via BoingBoing (http://www.boingboing.net))
http://www.boingboing.net/popscipuzzles1960.jpg

I totally don't get it. If anyone knows the answer, post it in invisible type I guess.

[Glenn]

<font color="white"> 3 3 25, there are two combinations that add up to 31, and one of the two is 15 15 1, making "are you the eldest" a relevant question </font>

edited for further clarity:

<font color="white"> The way you solve this problem is to start by taking the prime factorization for 225 (3*3*5*5), then find all combinations of 3 factors of 225 using this info (and not forgetting to include 1--such as 1*9*25). Next, take the sum of each set of factors and find a common sum that would require further information.</font>

[partygirluk]

x * y *z = 225

what are the possible values of x, y and z?

5, 5, 9

15, 15, 1

5, 15, 3

25, 3, 3

25, 9, 1

45, 5, 1

75, 3, 1

The house number is 31. The guy then knows the 3 are either 15, 15, 1 or 25, 3, 3

if it was 15, 15, 1 there would be no "eldest" so it is 15, 15, 1.

[bdk3clash]

<font color="white">Why can't they be 1, 9, and 25? Where does 31 come from?</font>

[Punker]

Answer in white:

<font color="white"> Options of 3 numbers whose product is 225:

1,1,225 (sum 227)
1,5,45 (sum 51)
1,15,15 (sum 31)
5,5,9 (sum 19)
5,3,15 (sum 23)
25,3,3 (sum 31)

If the house number was any of the unique solutions, the census taker would have the answer (say, if they lived in house #23, he'd know it was 3,5,15). So, since he still doesn't know the answer, the house # must be one of the non unique numbers. That leaves:

1,15,15 (sum 31)
25,3,3 (sum 31)

The respondent could not say he was older if he was one of the two 15 year olds, so that eliminates the 1,15,15 combination. That leaves the 3,3,25 combination and thats the ages.

</font>

See? Easy.

[Eurotrash]

edit: nevermind

[Punker]

Its process of elimination; it has to be 31 or "the product of our ages is 225 and the sum of our ages is the house number" would be sufficient to solve the problem.

[Thythe]

edit: nevermind...I think 3 of us asked the same question simultaneously.

[bdk3clash]

EDIT: This was much easier than figuring it out for myself. You guys are smart!

[ddubois]

x * y * z = 225

225 breaks down into 5x5x3x3, which leaves you a limited number of ways to formulate ages. x, y, and z, must either be one of: 1, 3, 5, 9, 15, 25, 45, 75, and some of those are mutually exclusive (if there's a 45 year old, then the other two people have to be 5 and 1).

Just looking at it for awhile, I notice that 25+3+3 = 31 and
15+15+1 = 31. I'm guessing the "are you the eldest" question is there to eliminate the 15,15,1 case, leaving the 25,3,3 case.

[mostsmooth]

<font color="white"> edit: ive removed the answer as its already been given
</font>

[Spaded]

This guy couldn't tell if the person who answered the door was 15 or 25, yet he could factor all combos of 225 that add up to 31 in a snap. Related to Sklansky?

[daryn]

[ QUOTE ]
This guy couldn't tell if the person who answered the door was 15 or 25, yet he could factor all combos of 225 that add up to 31 in a snap. Related to Sklansky?

[/ QUOTE ]

very nice

[YourFoxyGrandma]

I actually worked as a census taker last summer. People we're responding to me like this all the time. Drove me crazy.

[youtalkfunny]

I have two brothers, who were born 11 months apart.

If my brother answered the door, his "I'm the oldest" line would not help a bit.

Not to mention: how many households have a 15-year-old as the oldest resident?

Silly, silly puzzle.

[Spaded]

[ QUOTE ]
Not to mention: how many households have a 15-year-old as the oldest resident?

[/ QUOTE ]

The third world?