Odds for this?

[Piper Tim]

What are the odds of being dealt pocket aces (with no diamond) and then all 5 cards being diamonds.

If possible, show your math so I can see how it is calculated.

Party Poker Pot-Limit Hold'em, $ BB (10 handed) converter (http://www.selachian.com/tools/bisonconverter/hhconverter.cgi)
Preflop: Hero is UTG+2 with A/images/graemlins/club.gif, A/images/graemlins/spade.gif.
Flop: 8/images/graemlins/diamond.gif, 5/images/graemlins/diamond.gif, 3/images/graemlins/diamond.gif Turn: 2/images/graemlins/diamond.gif River: 4/images/graemlins/diamond.gif

[KJL]

C(3,2)/C(52,2) * C(13,5)/C(50,5) is the formula, I think.

[LetYouDown]

Yup...looks right to me about 727654 to 1. Assuming you already have the A-A, the first part drops out and you just have C(13,5)/C(50,5) which is a more reasonable 1645.3 to 1.

[hukilai]

He asked for odds for 1st AND 2nd things happen, so the first part should stay there...

[LetYouDown]

I'm well aware. He also asked for an explanation. I took it a step further and explained that the odds increase dramatically due to the A-A being a factor. My apologies for being thorough...and thanks for your analysis.