Noob ICM question

[playtitleist]

Researching ICM. Working through dethgrind's post. Can somebody explain how the % of prize pool is calculated in his example?

I've played with it, but am missing something elementary I'm sure.

Thanks.

1) you fold
UTG 800
Button 1500
SB 1900
you 3800
36.3% of the prize pool

2a) you call and lose
UTG 800
Button 2500
SB 1900
you 2800
31.5% of the prize pool

2b) you call and win
UTG 800
Button 0
SB 1900
you 5300
42.7% of the prize pool

2c) you call and split
UTG 800
Button 1350
SB 1900
you 3950
37.0% of the prize pool

[jgunnip]

Well first i believe you need a hand, then to go with that I think you opponent needs a hand. It looks like this is a situation where the button pushed and you're trying to figure out if you should call. This is entirely hand dependent since you have to calculate the chance your hand has vs his range of hands. then put what you've got here, with the percetnage chance that the even will happen and you've're on your way. also including the stack sizes before the hand was dealt is also helpful.

[Nicholasp27]

the % of prize pool IS ICM...

you plug those stacks into his icm calculator and it gives you a number (.384=38.4% or $3.84 in a 10/1 tourney)...the prize pool is 1st+2nd+3rd in sngs, or 10xBuy-in(not including rake)


your % of prize pool isn't as simple as "you have 30% of all chips so your % is .30" which is why we have the ICM formula for calculating it...

[Matt R.]

The % of prize pool corresponds to how many chips you have relative to the total chips in play. This is based on finish probabilities, which I believe is explained here (http://www.bol.ucla.edu/~sharnett/ICM/detail.html).

This web page (http://www.bol.ucla.edu/~sharnett/ICM/ICM.html) calculates it for you when you input the stack sizes of all the players left in the game.

[dethgrind]

This looks like the example straight from my old post. I plugged the stack sizes into my ICM calculator. I give a link to the calculator in that post.

[playtitleist]

It is. I see what I was missing now.

Thanks all. More questions follow I'm sure.