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I feel dumb. I'm assuming I'm just missing something obvious. In Powerball, you pick 5 numbers ranging from 1-53 and one "Powerball" ranging from 1-42. If you get them all right, you win. Shouldn't the odds of winning be 1 in 53*52*51*50*49*42 ~ 14,463,212,400?
According to their website, it's 1 in 120,526,770.00 (http://powerball.com/powerball/pb_prizes.asp)
Slade
08-07-2005, 01:00 AM
You dont have to choose the first five numbers in order so you're 120 times more likely to win.
Luzion
08-07-2005, 03:02 AM
[ QUOTE ]
I feel dumb. I'm assuming I'm just missing something obvious. In Powerball, you pick 5 numbers ranging from 1-53 and one "Powerball" ranging from 1-42. If you get them all right, you win. Shouldn't the odds of winning be 1 in 53*52*51*50*49*42 ~ 14,463,212,400?
According to their website, it's 1 in 120,526,770.00 (http://powerball.com/powerball/pb_prizes.asp)
[/ QUOTE ]
Dont use permutations. Use combinational probability since order does not matter.
C(53,5) * 42 = 120,526,770
which is (53!/5!48!) * 42
or simplied [ (53*52*51*50*49)/(5*4*3*2) ] * 42
= 120,526,770
This is assuming the Powerball number can be a duplicate of one of the regular 5 I believe.
[ QUOTE ]
You dont have to choose the first five numbers in order so you're 120 times more likely to win.
[/ QUOTE ]
well duh. like i said, probably just missing something obvious. good thing i'm not looking to make a career out of something probability-related like being an actuary.
aw crap.
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