odds based on outs

[cyberer]

is there a simplified calculation in holdem to determine the odds of hitting your hand based on the number of outs you have in the deck? I'd imagine there is a separate calculation for the turn and river.

[jba]

your odds are

(cards remaining - outs) to (outs)

if you have 5 outs on the turn, then your odds are:

(46-5) to 5, or 41 to 5.

[LethalRose]

X to 1 odds = You hit your hand 1 out of (X + 1) times
X to 1 odds = 1 / (X + 1) = % chace to hit your hand

(Example: 3 to 1 odds = 1 / 4 = 25% chance to hit your hand)

Outs Flop% Turn% Flop Odds Turn Odds Draw Type
2 8% 4% 12 22 Pocket Pair -> Set
3 13% 7% 7 14 Single Overcard Draw
4 17% 9% 5 10 Gut Shot, Two Pair -> Full House
5 20% 11% 4 8 One Pair -> Two Pair or Set, Gut+Backdoor
6 24% 13% 3.2 6.7 No Pair -> Pair, Two Overcard Draw
7 28% 15% 2.6 5.6 Set -> Full House or + (not counting extra turn outs)
8 32% 17% 2.2 4.7 Open Straight Draw
9 35% 19% 1.9 4.1 Flush Draw, Open+Backdoor Draw
10 42% 22% 1.6 3.6
11 42% 24% 1.4 3.2
12 45% 26% 1.2 2.8 Flush+Gut Draw
13 48% 28% 1.1 2.5
14 51% 30% 0.95 2.3
15 54% 33% 0.85 2.1 Flush+Open Draw
16 57% 34% 0.75 1.9 Flush+Open+One Overcard
17 60% 37% 0.66 1.7








Memorize that.