Harrington's SHAL Theory (question for those who read v2)

In HoH vII he explains his SHAL process for going all in against 4 players yet to act and calculating his chances and expectations assuming only 1 of them calls. How would you do these SHAL calculations if you think 2, 3, or even all 4 of them will call?

[stone_7]

[ QUOTE ]
In HoH vII he explains his SHAL process for going all in against 4 players yet to act and calculating his chances and expectations assuming only 1 of them calls. How would you do these SHAL calculations if you think 2, 3, or even all 4 of them will call?

[/ QUOTE ]

If you are expecting 4 callers you had better have a monster or a very small stack. No analysis needed.

Well those are the times I would try using this anyway, especially if im a small stack.
And sometimes online you manage to find tables where everyone just feels like going all in with any 2 cards.

[erby]

if you think you're getting 2,3, or 4 callers, there is a good chance that people will get there money in the pot even if you fold. So I think you have to just give the big stack a chance to bust another guy and bump you up in the money, especially if you're the short-stack (unless you hold a monster).

ERBY /images/graemlins/spade.gif