lilkunta2
07-20-2005, 05:22 AM
was doing some thinking. need some verification (if right) and correction (if wrong)
there are 8 ways to make a pocket pair, and 16 ways to make any 2 unsuited cards. I take a sample of top hands let's say....
AA
KK
QQ
JJ
AK (suited or unsuited)
AQ (suited or unsuited)
now,,, you have 3 pocket pairs for 4x8=32 combinations and you have 2 off rank hands 16x2= 32
so the total is 64
there are 1326 combinations for hands,,,,
64/1326=.0482 lets round up to .05 for arguments sake.
this means that the chances of getting dealt on of these hands is (about) 5%
and this also means that the chance of any person at a 10 person table having one of these hands is (.05x10) or %50
this means that once in every 2 rounds at a full table, you will get dealt one of these hands.
is this correct? becuase it seems like hands like that don't come around that often. please correct me if i am wrong.
thanks
there are 8 ways to make a pocket pair, and 16 ways to make any 2 unsuited cards. I take a sample of top hands let's say....
AA
KK
JJ
AK (suited or unsuited)
AQ (suited or unsuited)
now,,, you have 3 pocket pairs for 4x8=32 combinations and you have 2 off rank hands 16x2= 32
so the total is 64
there are 1326 combinations for hands,,,,
64/1326=.0482 lets round up to .05 for arguments sake.
this means that the chances of getting dealt on of these hands is (about) 5%
and this also means that the chance of any person at a 10 person table having one of these hands is (.05x10) or %50
this means that once in every 2 rounds at a full table, you will get dealt one of these hands.
is this correct? becuase it seems like hands like that don't come around that often. please correct me if i am wrong.
thanks