View Full Version : XY, XY, XY, ZZ, flop comes XYZ - odds?
btetreau
07-12-2005, 03:35 PM
Hey All,
Ran into this recently in a MTT, table was full (10 heads) and I got AK, raised, and 3 callers came along. Flop was AK5, everyone went allin, and the 4 hands were AK, AK, AK, 55.
So, what are the chances that the flop will come XYZ if 3 of the 10 people hold XY and a fourth holds ZZ?
Thanks in advance.
MickeyHoldem
07-12-2005, 04:52 PM
There are only 1 X&Y left and 2 Z's so there are only 2 flops out of the 44c3 possible flops left.... so
= 2/13244 = 1 in 6622 or .000151012
Presto! there's your answer!
<sorry - couldn't resist>
mtrubo
07-18-2005, 08:15 AM
just curious; did the turn and/or river help?
schafdawg
07-18-2005, 09:10 PM
[ QUOTE ]
just curious; did the turn and/or river help?
[/ QUOTE ]
It would be crazy if one of the AKs hit a flush during that. If no AKs, then turn and river help no one. (Can't tell if you were asking a serious question or not)
spaminator101
08-01-2005, 07:11 PM
1 xy left two z left
1/50*1/49*1/24=1/58800
BruceZ
08-01-2005, 08:47 PM
[ QUOTE ]
1 xy left two z left
1/50*1/49*1/24=1/58800
[/ QUOTE ]
1/44 * 1/43 * 2/42 * 6 = 1/6622
There are 44 cards left not 50, and the 3 cards can come in 6 different orders.
spaminator101
08-01-2005, 10:42 PM
sry y is order important
BruceZ
08-02-2005, 12:03 AM
[ QUOTE ]
sry y is order important
[/ QUOTE ]
If we don't multiply by 6, then we are computing the probability of XYZ in exactly that order. We don't care about the order, so we multiply by 6 to allow any possible order.
spaminator101
08-02-2005, 12:54 PM
ok thank you
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