brimstone1
07-12-2005, 07:18 AM
[It seems I'm going to be running into situations like this often during my bubble-workout, so I'm going to hopefully post as I go along]
Okay, so I've been fooling around with different scenarios in SnGPT, I'm wondering why exactly the following result occurs, theoretically.
Set the sngpt to:
$10+$1 (anything with 800 chips)
Players: 4
Blinds: 75/150
Hand: Anything you want
Calling range: Maniac
BB - 1000 chips.
SB - 2500 chips.
BTN - 2500 chips.
CO - 2000 chips.
You are SB, and you are pushing into the BB.
Now, with BB at 2500 chips, for instance, J3s (the hand I chose), will have +0.7% EV.
Okay. So with 2.5x the amount of chips of the pushee, the pusher has +0.7% EV with J3s. Fine.
Now, make BB 3500, and adjust BTN/CO to compensate for the chip total, and try again.
EV +0.6%.
The more chips you have relative to your opponent, the less EV it is.
Why?
Shouldn't it be more less "-EV" to push with more chips (or, at least a stack big enough to cover the pushee) since you can't be eliminated on that one hand?
I think I figured it out while writing this post... It's because Fold EV drops from 34.4% to 29.1%, but EV Push drops from 35.0% to 29.8%... its because Fold EV is relatively larger when you have more chips, since you can do quite OK without this particular hand.
Well, even if I think I solved the "mystery," can someone verify this?
Okay, so I've been fooling around with different scenarios in SnGPT, I'm wondering why exactly the following result occurs, theoretically.
Set the sngpt to:
$10+$1 (anything with 800 chips)
Players: 4
Blinds: 75/150
Hand: Anything you want
Calling range: Maniac
BB - 1000 chips.
SB - 2500 chips.
BTN - 2500 chips.
CO - 2000 chips.
You are SB, and you are pushing into the BB.
Now, with BB at 2500 chips, for instance, J3s (the hand I chose), will have +0.7% EV.
Okay. So with 2.5x the amount of chips of the pushee, the pusher has +0.7% EV with J3s. Fine.
Now, make BB 3500, and adjust BTN/CO to compensate for the chip total, and try again.
EV +0.6%.
The more chips you have relative to your opponent, the less EV it is.
Why?
Shouldn't it be more less "-EV" to push with more chips (or, at least a stack big enough to cover the pushee) since you can't be eliminated on that one hand?
I think I figured it out while writing this post... It's because Fold EV drops from 34.4% to 29.1%, but EV Push drops from 35.0% to 29.8%... its because Fold EV is relatively larger when you have more chips, since you can do quite OK without this particular hand.
Well, even if I think I solved the "mystery," can someone verify this?