TJD
05-04-2005, 05:31 AM
Cross Posted from HUSH forum.
We make money from the other players' mistakes. The NET result at every table is that the players lose the rake.
This means that whether the table is 6 brilliant players or 6 appalling players the "table" will lose the same. The 6 exellent players will be making virtually NO mistakes. The 6 bad players will be making loads.
I think this must mean that the more bad players there are at a table, the more mistakes they make in total but the actual value of each mistake is less. So we get a formula M x V (number of Mistakes x average Value of mistake). This is logical since on a table of bad players there will be better odds available for their "poor" decisions. In fact some of them might even be right
We then need to subtract from these mistakes R for the rake.
So we get MV-R as the profit available to the table.
In a table of excellent players, MV will be close to zero, so the players lose R approximately and the table becomes unplayable for profit.
However, as Gary Carson says "Just ONE bad player" can make a table playable. The implication here is that the bad player has a high M and that each V is high.
I have always believed that I would prefer a table of 5 bad players but if they make smaller mistakes and sometimes even make a correct decision because of the looseness of the other bad players, how much extra advantage do I actually gain?
What are peoples views on this? Other than ensuring that there ARE bad players to sweeten the pot, how mcuh do we think this changing value of "V" affects our table selection?
T
We make money from the other players' mistakes. The NET result at every table is that the players lose the rake.
This means that whether the table is 6 brilliant players or 6 appalling players the "table" will lose the same. The 6 exellent players will be making virtually NO mistakes. The 6 bad players will be making loads.
I think this must mean that the more bad players there are at a table, the more mistakes they make in total but the actual value of each mistake is less. So we get a formula M x V (number of Mistakes x average Value of mistake). This is logical since on a table of bad players there will be better odds available for their "poor" decisions. In fact some of them might even be right
We then need to subtract from these mistakes R for the rake.
So we get MV-R as the profit available to the table.
In a table of excellent players, MV will be close to zero, so the players lose R approximately and the table becomes unplayable for profit.
However, as Gary Carson says "Just ONE bad player" can make a table playable. The implication here is that the bad player has a high M and that each V is high.
I have always believed that I would prefer a table of 5 bad players but if they make smaller mistakes and sometimes even make a correct decision because of the looseness of the other bad players, how much extra advantage do I actually gain?
What are peoples views on this? Other than ensuring that there ARE bad players to sweeten the pot, how mcuh do we think this changing value of "V" affects our table selection?
T