PDA

View Full Version : Couple of problems I am struggling with...


SGS
04-28-2005, 08:55 PM
You draw five cards out of the deck. If there are 3 or more of one suit you keep those in hopes of getting a flush and throw away the other two. For example you draw 3 hearts and 2 clubs, you throw away the clubs and draw two more cards. What is the probability that you will have a flush?

My thought was it should be the sum of the following:
Draw 2: (13/52)*(12/51)*(11/50)*(39/49)*(38/48)*(10/47)*(9/46)

Draw 1: (13/52)*(12/51)*(11/50)*(10/49)*(38/48)*(9/47)

Dealt to you: (13/52)*(12/51)*(11/50)*(10/49)*(9/48)

2nd problem is 1 out of 1000 births result in fraternal twins; 1 out of 1500 births result in identical twins. Identical twins must be the same sex while the sexes of fraternal twins are independent. If two girls are twins what is the probability they are fraternal twins?

This one I am really lost on and don't know where to begin.

Thanks in advance for any help.

SGS

Filip
04-28-2005, 10:58 PM
[ QUOTE ]
You draw five cards out of the deck. If there are 3 or more of one suit you keep those in hopes of getting a flush and throw away the other two. For example you draw 3 hearts and 2 clubs, you throw away the clubs and draw two more cards. What is the probability that you will have a flush?


[/ QUOTE ]

Probability of drawing 3/5 hearts from 52 cards:
HYP(3,5,13,52) = 0.081542617

Probability of drawing 2/2 hearts from 47 cards:
HYP(2,2,10,47) = 0.041628122

So the probability of making a flush (hearts) is:
0.081542617 * 0.041628122 = 0.003394466

I am actually not certain if this should be x 4 since the suit in itself is unimportant, its 5 am i could not figure out what i had playing Omaha so i may be way off, but i think you should multiplay with 4.

Probability that you will have a flush: 0.013577864 ~= 1.4%

carsten
04-30-2005, 02:13 AM
[ QUOTE ]

2nd problem is 1 out of 1000 births result in fraternal twins; 1 out of 1500 births result in identical twins. Identical twins must be the same sex while the sexes of fraternal twins are independent. If two girls are twins what is the probability they are fraternal twins?


[/ QUOTE ]

This is a good example for conditional probabilities (See http://mathworld.wolfram.com/ConditionalProbability.html), but you can tackle the problem intuitively.

It helps to bring the probabilities to a common denominator. The smallest common denominator of 1000 and 1500 is 3000, but for reasons that will be clear in a moment, I want the numerator for the probability of fraternal twins to be an even number, so I'll choose 6000 as the common denominator.

Hence, P(fraternal twins) = 6/6000 and P(identical twins) = 4/6000.

Since the genders of fraternal twins are independent, half the fraternal twin births will be same-sex, the other half will be mixed-sex. This gives me

P(mixed-sex fraternal twins) = 3/6000 and P(same-sex fraternal twins) = 3/6000.

Now let's get back to the problem: Given that a same-sex twin birth has occurred, what is the probability that it is a fraternal twin birth? To answer this, we simply have to find the ratio of fraternal same-sex twin births to the total number of same-sex twin births.

Out of 6000 births, there are 3 fraternal same-sex twin births and 4 identical (necessarily same-sex) twin births, for a total of 7 same-sex twin births. Of those 7, 3 are fraternal, so the answer is 3/7.

I'll leave it as an exercise for the reader to convince themselves that any other choice of population size would yield the same result.

Hope this helps,

Carsten.

Masquerade
04-30-2005, 06:15 AM
If you start with 3 there are 10 left out of 47. You must hit on both cards so 10/47 * 9/46 = 0.04+

If you start with 4 there are 9 left out of 47. You only need to hit at least once, or equivalently NOT miss twice. So chance is (1 - 38/47 * 37/46) = 0.35

Imagine 3,000,000 births. 3,000 will be fraternal twins (750 BB, 1,500 BG, 750 GG) and 2,000 will be identical twins (1,000 BB and 1,000 GG).

So chance that GG is fraternal is 3/7.