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View Full Version : 3 consecutive hands: KK,AA,AK


BillFranklin
03-16-2005, 09:42 PM
what are odds of these 3 hands back to back to back: KK,AA,AK (happened to me today.. couldn't believe it)

is it (6/1326)*(6/1326)*(16/1326)=0.247060189
405 to 1 against.
not sure if this correct, the number seems alittle low)

gaming_mouse
03-16-2005, 10:13 PM
You did the calc right, but the arithmetic wrong.

It's 1 in 4,047,697.87

TaintedRogue
03-20-2005, 10:24 AM
Your correct, however, you didn't answer his question....which he articulated poorly. What he was saying, was: I've played a total of X amount of hands on line since I started and was finally dealt AK,AA,KK three hands in a row.
Now, if he had asked: "What are the odds of me logging into my poker site, getting into a game and being dealt AK, AA & KK the first three hands.....well, then you are correct.
You must also take into consideration that he would have been here posting he phenomenon if he had been dealt AA, KK and the AA again. OR, AA,KK, QQ or etc., so you have to take into consideration all those various hands with extremely high odds against catching in 3 consecutive hands.
However, you did do a good job of pacifying the poster.

MickeyHoldem
03-20-2005, 12:12 PM
so lets assume you see 300 hands during an online session, and we don't worry about what order we get these 3 hands in... so the odds become 6/52c2 * 6/52c2 * 16/52c2 * 6 of seeing these 3 hands back to back in any order.

Now we have 298 chances during the session to see this phenom. occur (it's actually a little less than 298, but we'll use 298 and be farily accurate), so we plug this into excel function BINOMDIST(1,6/52c2 * 6/52c2 * 16/52c2 * 6,298,false) = 0.0004415381435

So you should see this happen about once every 2265 sessions.

I'm not 100%(not even 20%) sure how to calculate the exact number of trials for this problem since the 3 hands have different chances of occuring!!... I got 295.876702 but I'm sure that ain't right!! Anyone???

Siegmund
03-20-2005, 07:51 PM
If you want the odds of precisely KK, AA, and AK, in that order, your calculation is set up right.

More likely, though, what you want is something else. Either the odds of "holding only aces and kings for three hands in a row", which is (28/1296)^3, or the odds of "holding a starting hands this powerful or more so three hands in a row." The best starting hands: AA KK QQ JJ AKs TT AQs AKo. You didn't say whether your AK was suited or not. If so, it's again (28/1296)^3; if you just want AKo or better three times in a row, (50/1296)^3.

These are about 1 in 99,000 and 1 in 17,400 respectively. Uncommon - but common enough that many 2+2 regulars will see this several times a year.

This afternoon, for instance, I sat down at a table was dealt pockets pairs on my second, third, fourth, fifth, and sixth hands. (tens twice, nines, sevens, and fives - no monsters.) Not seen it before. But lots of weird things eventually happen.

jpg7n16
03-20-2005, 08:11 PM
Shouldn't it be set up as

(4/52)*(3/51)*(4/52)*(3/51)*(4/52)*(4/51) =

4/32,381,583

or 1 in 8,095,395.75

?? Shouldn't that be how it is set-up ??

MickeyHoldem
03-20-2005, 08:35 PM
[ QUOTE ]
Shouldn't it be set up as

(4/52)*(3/51)*(4/52)*(3/51)*(4/52)*(4/51) =

[/ QUOTE ]

(4/52)*(3/51)*(4/52)*(3/51)*(8/52)*(4/51)

That AK gets 8 chances for the first card!

jpg7n16
03-21-2005, 05:45 PM
I didn't think about that /images/graemlins/smile.gif thanks!

planB
03-27-2005, 10:37 AM
In a recent sng: KK KK KK KJ (4 hands in a row - all 3 pp held up).

popniklas
03-28-2005, 09:47 AM
</font><blockquote><font class="small">Svar till:</font><hr />
In a recent sng: KK KK KK KJ (4 hands in a row - all 3 pp held up).

[/ QUOTE ]

yikes, that's one nice run of cards. i once won a party poker sng with AA, AA, 44 as my three last hands. opponent started whining like crazy, it was pretty funny. /images/graemlins/smile.gif

SA125
03-28-2005, 02:00 PM
I was recently dealt KK, AA and KK consecutively and lost badly on all 3 hands. It was in the beginning of one of those - 3% hands won/12% flops seen won - sessions online.

I quickly gave up because, no matter what they say about randomness, there are times you will lose no matter what the hand or how many tables. The draws don't catch and the big hands don't hold up. White flag time.

Jazza
03-28-2005, 06:17 PM
I've had that exact same sequence before, I raised preflop every time and got no callers all three times

I just thought "meh" and kept on playing

xorbie
03-28-2005, 08:44 PM
I was once dealt AKs, AA then AA. First hand I caught the nut flush on the river, second hand and third hand I flopped a set both times (didn't get payed much).

Now how 'bout those odds.

Voltron87
03-28-2005, 11:22 PM
I had KK, AA, then a set of 10s back to back.


What are the odds of getting T9s, K2s, and Ajo back to back guys its teh nuts so crazy!

sawseech
03-29-2005, 02:07 AM
the same as being dealt 33 72 and 88 in back to back hands
;p

scdavis0
03-31-2005, 12:14 AM
[ QUOTE ]
the same as being dealt 33 72 and 88 in back to back hands
;p

[/ QUOTE ]

Wrong.

Do you see why?

Richie Rich
04-26-2005, 09:01 PM
[ QUOTE ]
Wrong.

Do you see why?

[/ QUOTE ]
I see why (because we're asking for the probability of specific hands falling back-to-back-to-back), but it may not be so obvious to others in this forum. No disrepect, but instead of making short, patronizing comments like the one quoted above, or

[ QUOTE ]
Call.. and it's not close

[/ QUOTE ]

just explain your line of reasoning. Makes your ability to effectively communicate with others that much better. /images/graemlins/smile.gif